x^2+25x+145=-11

Solution for x^2+25x+145=-11 equation:

x^2+25x+145=-11

We move all terms to the left:

x^2+25x+145-(-11)=0

We add all the numbers together, and all the variables

x^2+25x+156=0

a = 1; b = 25; c = +156;
Δ = b2-4ac
Δ = 252-4·1·156
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-1}{2*1}=\frac{-26}{2}
=-13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+1}{2*1}=\frac{-24}{2}
=-12
$